The EASA
ATPL Mass and Balance
test bank contains questions pertaining to
031-03-02 Calculation of CG
. The following list contains only a relatively small percentage of the pertinent
questions. Our software, which you are free to download now at no cost, will
generally contain a much more complete set of questions associated with this
test bank. This list is intended only to familiarize you in a general way with
the questions of the
Mass and Balance
test bank.
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That said, while the following questions are intended
as a general familiarization tool, this list may not be up-to-date nor accurate.
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| Sample Questions
from the EASA ATPL
Mass and Balance
Test Bank |
- (Refer to figure L235)Using the load and trim sheet attached, calculate the CG at zero fuel mass.
- The aft CG limit of an aircraft is 80 in aft of the datum. The loaded CG is found to be at 80.5 in aft of the datum.The mass is 6400 lb. How much mass must be removed from a hold situated 150 in aft of the datum to bring the CG onto the aft limit?
- The MAC is 58 inches. The C.G. limits are from 26% to 43% MAC. If the C.G. is found to be at 45.5% MAC, how many inches is it out of limits?
- The loaded mass of the aircraft is found to be 1850 lb and the CG moment 154 000 lb in. How much mass must be moved from the forward hold 40 inches aft of the datum, to the rear hold, 158 inches aft of the datum, to bring the CG on to the forward limit? CG limits are 86 inches fwd and 90 inches aft.
- A turbojet aeroplane has a planned take-off mass of 190 000 kg. Following cargo loading, the crew is informed that the centre of gravity at take-off is located at 38 % MAC (Mean Aerodynamic Cord) which is beyond limits.The captain decides then to redistribute part of the cargo load between cargo 1 (3.5 m from reference point) and cargo 4 (20.39 m from reference point) in order to obtain a new centre of gravity location at 31 % MAC.Given:Distance from reference point to leading edge: 14 mLength of MAC = 4.6 m.He asks for a transfer of:
- (For this Question use CAP 696 - Figures 2.1 - 2.4)With respect to a single-engine piston powered aeroplane, determine the zero fuel moment (lbs.In./100) in the following conditions:Basic Empty Mass: 2415 lbsArm at Basic Empty Mass: 77,9 In Cargo Zone A: 350 lbsBaggage Zone B: 35 lbsPilot and front seat passenger: 300 lbs (total)
- A loaded aircraft weighs 4200 Ib with a C of G 9 inches AFT of the datum. An extra 200 Ib is loaded into the aircraft 40 inches FWD of the datum. The new C of G position is:
- (Refer to figure L227)Using the data given at the appendix, determine which of the following correctly gives the values of the Zero Fuel Mass (ZFM) of the aeroplane and the load index at ZFM:
- Given:Aeroplane mass = 36 000 kgCentre of gravity (cg) is located at station 17 mWhat is the effect on cg location if you move 20 passengers (total mass = 1 600 kg) from station 16 to station 23?
- Given:C of G is located at STN 15Aeroplane mass is 3650 IbsWhat is the effect on the C of G if you move baggage (total mass 64 Ib) from STN 14 to STN 20?
- (Refer to figure L227)From the data given at the appendix and assuming a fuel index shift of - 5.7 from the ZFM loaded index, determine which of the following, is the correct value (percentage MAC) for the position of the centre of gravity at Take Off Mass:
- What is the CG as a percentage MAC of the fully loaded aircraft below?BEM 12000 kgArm 3mCG 25 % MACMAC 2mItem Balance arm:Front seats 2.5 mRear seats 3 mFuel SG 0.74Fuel 410 litresFuel arm 2.5 mRear seats EmptyPilot 80 kgPassenger 80 kg
- An aircraft with a BEM of 135 000 Kg acting at an arm of +15 m from datum is loaded with:Freight of 50 000 Kg centred 12m aft of datumFuel of 80 000 litres @ SG 0.8 centred 18m aft of datumCalculate the new CG for this aircraft:
- Given:Total mass: 7500 kgCentre of gravity (cg) location station: 80.5Aft cg limit station: 79.5How much cargo must be shifted from the aft cargo compartment at station 150 to the forward cargo compartment at station 30 in order to move the cg location to the aft limit?
- An aeroplane with a two wheeled nose gear and four main wheels rests on the ground with a single nose wheel load of 725 kg and a single main wheel load of 6000 kg. The distance between the nose wheels and the main wheels is 10 meters. How far is the centre of gravity in front of the main wheels?
- (For this Question use CAP 696 - Figure 4.12)Prior to take-off there is a change in destination and so the pilot decides to take 2,000 kg of fuel less. Using the Load and Trim Sheet, calculate the new Take-off mass and CG position.
- An item weighting 1000 kgs is loaded at a station 10m aft of the present CG, which is 15m aft of the reference datum. The moments are:
- (Refer to CAP696 figure 4-7)If a passenger moves from a seat position corresponding to the balance arm at zone D to a position corresponding to the balance arm at zone F, what distance will the passenger have travelled and how many seat rows will he have passed?
- An aircraft has a mass of 19 700 kg with the CG located at + 300 inches. A mass of 287 kg is added at an arm of - 98.3 inches.Calculate the new CG location:
- If 390 lbs of cargo are moved from compartment B (aft) to compartment A (forward), what is the station number of the new centre of gravity (CG)?Given:Gross mass: 116 500 lbsPresent CG station: 435.0Compartment A station: 285.5Compartment B station: 792.5
- (Refer to CAP 696 figure 4-9)The total mass of an aeroplane is 145 000 kg and the centre of gravity limits are between 4.7 m and 6.9 m aft of the datum. The loaded centre of gravity position is 4.4 m aft. How much mass must be transferred from the front to the rear hold in order to bring the out of limit centre of gravity position to the foremost limit?
- (Refer to CAP 696 figure 4-7 & 4-8)Without the crew, the mass and longitudinal CG position of the aircraft are 6 000 kg and 4,70m.the mass of the pilot is 90 kg the mass of the co-pilot is 100 kg the mass of the flight engineer is 80 kgWith the crew, the mass and longitudinal CG position of the aircraft are:
- The C of G of an aircraft is 196 inches aft of datum at an all up mass on 12 500 lbs. If 200 lbs of baggage is moved from FS 325 to FS 120, the new C of G will be:
- (Refer to CAP696 figure 2-5)The CG is on the lower of the fwd CG limits:
- What freight must be removed from a hold 30m aft of the datum to move the CG from 22.62m aft of the datum to 20m aft of the datum, aeroplane mass before removal = 112 000 lbs:
- (For this Question use CAP 696 - Figure 4.12)When adjusting the CG index for the fuel load, why is the line moved to the left as a minus index?
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Mass and Balance
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